(3/(2x+10))-((3x)/(x^2-25))=0

Solution for (3/(2x+10))-((3x)/(x^2-25))=0 equation:

(3/(2x+10))-((3x)/(x^2-25))=0


Domain of the equation: (2x+10))!=0

x∈R



Domain of the equation: (x^2-25))!=0

x∈R


We calculate fractions


(-6x^2-30x)/((2x+10))*x^2+(3x^2-75)/((2x+10))*x^2=0

We multiply all the terms by the denominator


(-6x^2-30x)+(3x^2-75)=0

We get rid of parentheses

-6x^2+3x^2-30x-75=0

We add all the numbers together, and all the variables

-3x^2-30x-75=0

a = -3; b = -30; c = -75;
Δ = b2-4ac
Δ = -302-4·(-3)·(-75)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{30}{-6}=-5$